(3x-7)^2=(3x-7)(2x-1)

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Solution for (3x-7)^2=(3x-7)(2x-1) equation: 



(3x-7)^2=(3x-7)(2x-1)

We move all terms to the left:

(3x-7)^2-((3x-7)(2x-1))=0

We multiply parentheses ..

-((+6x^2-3x-14x+7))+(3x-7)^2=0



We calculate terms in parentheses: -((+6x^2-3x-14x+7)), so:

(+6x^2-3x-14x+7)

We get rid of parentheses

6x^2-3x-14x+7

We add all the numbers together, and all the variables

6x^2-17x+7

Back to the equation:

-(6x^2-17x+7)



We get rid of parentheses

-6x^2+17x+(3x-7)^2-7=0

We move all terms containing x to the left, all other terms to the right

-6x^2+17x+(3x-7)^2=7

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